Python sqlite insert multiple rows2/28/2024 ![]() SELECT Playlist.Name, COUNT(PlaylistTrack.TrackId) AS TotalTracks FROM Playlist INNER JOIN PlaylistTrack ON Playlist.PlaylistId = PlaylistTrack.PlaylistId GROUP BY Playlist.Name Thought: I can use a SELECT statement to get the total number of tracks in each playlist.Īction Input: SELECT Playlist.Name, COUNT(PlaylistTrack.TrackId) AS TotalTracks FROM Playlist INNER JOIN PlaylistTrack ON Playlist.PlaylistId = PlaylistTrack.PlaylistId GROUP BY Playlist.Name Thought: I should look at the schema of the Playlist and PlaylistTrack tables to see what columns I can use. Observation: įinal Answer: The customers from the USA spent the most, with a total of $523.06. Thought: I should query the Invoice and Customer tables to get the total sales per country.Īction Input: SELECT c.Country, SUM(i.Total) AS TotalSales FROM Invoice i INNER JOIN Customer c ON i.CustomerId = c.CustomerId GROUP BY c.Country ORDER BY TotalSales DESC LIMIT 10 InvoiceId CustomerId InvoiceDate BillingAddress BillingCity BillingState BillingCountry BillingPostalCode Totalġ 2 00:00:00 Theodor-Heuss-Straße 34 Stuttgart None Germany 70174 1.98Ģ 4 00:00:00 Ullevålsveien 14 Oslo None Norway 0171 3.96ģ 8 00:00:00 Grétrystraat 63 Brussels None Belgium 1000 5.94 Thought: I should look at the schema of the relevant tables to see what columns I can use.įOREIGN KEY("SupportRepId") REFERENCES "Employee" ("EmployeeId")ĬustomerId FirstName LastName Company Address City State Country PostalCode Phone Fax Email SupportRepIdġ Luís Gonçalves Embraer - Empresa Brasileira de Aeronáutica S.A. Observation: Invoice, MediaType, Artist, InvoiceLine, Genre, Playlist, Employee, Album, PlaylistTrack, Track, Customer Thought: The table is called PlaylistTrackįinal Answer: The PlaylistTrack table contains two columns, PlaylistId and TrackId, which are both integers and are used to link Playlist and Track tables. Thought: I should check the spelling of the table Observation: Error: table_names not found in database Thought: I should look at the schema of the PlaylistSong table Observation: Genre, PlaylistTrack, MediaType, Invoice, InvoiceLine, Track, Playlist, Customer, Album, Employee, Artist Please let me know if there is anything else I can help you with. Here are three sample rows from the `PlaylistTrack` table: Here is the schema of the `PlaylistTrack` table: ![]() It is a junction table that represents the relationship between playlists and tracks. */The `PlaylistTrack` table has two columns: `PlaylistId` and `TrackId`. Invoking: `schema_sql_db` with `PlaylistTrack`įOREIGN KEY("TrackId") REFERENCES "Track" ("TrackId"),įOREIGN KEY("PlaylistId") REFERENCES "Playlist" ("PlaylistId") Album, Artist, Track, PlaylistTrack, InvoiceLine, sales_table, Playlist, Genre, Employee, Customer, Invoice, MediaType
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